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Food goes in here
Lol, this topic has gone off on a tangent, but I don't blame you guys, this run's taking longer than Duke Nukem Forever.:P Or whatever the hell its called now.
Existence as you know it is over
Quote:
So e^x goes up to the operator and says, "I'm e^x. You can't do anything to me!"
And the operator says, "Hi, I'm d/dy."

Cheesy


If I remember anything from multivariable,      d(ex) / dy          =        0          right?       
Invisible avatar
Quote:
Lol, this topic has gone off on a tangent, but I don't blame you guys, this run's taking longer than Duke Nukem Forever.:P Or whatever the hell its called now.



Now i'm waiting for an edit that goes:
Finally...scenes from Half-Life in Half an Hour!
No way, they've actually been working on it??

Wink
XXY
If carrots were drugs, rabbits would be fucked up.
give me your eyes!!!
Quote:

If I remember anything from multivariable,       d(ex) / dy          =         0           right?        


d(ex) / dy = ex

...

but I don't get the joke!!
Quote:

d(ex) / dy = ex

...

but I don't get the joke!!


Sorry but you are wrong, the answer is 0 because e^x is not a function of y, thus it's derivative in relation to y (sorry if I am using the wrong words, don't know the correct terms in English) is 0.

-C2
Edit history:
CannibalK9: 2006-10-25 01:08:14 am
give me your eyes!!!
Quote:

Sorry but you are wrong, the answer is 0 because e^x is not a function of y, thus it's derivative in relation to y (sorry if I am using the wrong words, don't know the correct terms in English) is 0.

-C2


Bah, I'm an idiot... I mean... that's a really poor joke!!
&lt;3
Hay guyz what's goin' on in this thread.
I love YaBB 1G - SP1!
Quote:
Hay guyz what's goin' on in this thread.


Maths

They're gonna use maths to make the run come out faster
Edit history:
tagh_azog: 2006-10-25 01:08:02 pm
piece of cake!
lool guys!

now: f(x,y)=(X²-Y²)/(1-X)  (R-{1})

calculate df/dxdy
and after, df/dydx

what can you say me about this function, according to Cauchy, to prevent the coming of spider's run? Grin Grin Grin ^^

I loved Highschool, knowing that it's finished lol

         
0.9999999 = 1
Existence as you know it is over
Quote:
lool guys!

now: f(x,y)=(X²-Y²)/(1-X)  (R-{1})

calculate df/dxdy
and after, df/dydx


df/dxdy  =  df/dydx  =  [(-2y)(x2 - 2x + 1)] / [(1 - x)4]
Edit history:
tagh_azog: 2006-10-25 01:43:13 pm
piece of cake!
yeaaah, there is a demonstration which prove that, it was funny because it seemed to be impossible^^
but there is a little mistake in this demonstration, which create this error Grin
piece of cake!
Quote:

df/dxdy  =  df/dydx  =  [(-2y)(x2 - 2x + 1)] / [(1 - x)4]



normally, it was 2Y/(1-X)² ^^
Existence as you know it is over
how can that be?
piece of cake!
Edit your post and give me the details of your calculs, you may find the same! Iwill found the demonstration for 0,9999=1, if I remember how to get it Grin
Edit history:
CannibalK9: 2006-10-25 02:06:25 pm
give me your eyes!!!
Isn't that just:

x = 0.999999...

10x = 9.999999...

9x = 10x - x = 9

x = 1

0.999999... = 1

I don't remember too well... I suspect there's a more complicated way but that's easy enough.
Edit history:
tagh_azog: 2006-10-25 02:18:52 pm
piece of cake!
it is like this but it is not 10x-x=9 Wink

EDIT: infact, it may be this demonstration...I thought it was another mistake but now, I think 10x-x=9 is the good mistake in the demonstration Grin
Existence as you know it is over
True, you can't exactly subtract infinitesimals from each other.
give me your eyes!!!
You're just cancelling out the infintesimally bit. I see nothing wrong with it myself, infinity is too big to think about rationally so whether it's '1' or 'as close as possible to 1' is a matter of opinion.
piece of cake!
Quote:
You're just cancelling out the infintesimally bit. I see nothing wrong with it myself, infinity is too big to think about rationally so whether it's '1' or 'as close as possible to 1' is a matter of opinion.


anyway, 0,999999...=1 is basically wrong^^, because it is a limit, not a bascial equal. Wink
I love YaBB 1G - SP1!
Less calculus, more Half-Life.
piece of cake!
Quote:
Less calculus, more Half-Life.


your function is wrong, because there is no more half life for the moment^^
Quote:
0.999... (also denoted 0.bar{9} or 0.dot{9}) is a recurring decimal which is exactly equal to 1. In other words, the symbols 0.999… and 1 represent the same real number.

Bahahaha, the featured article for today on [link=http://en.wikipedia.org/wiki/Main_Page]Wikipedia[/link] is the article on .999...
Edit history:
dex: 2006-10-25 05:55:07 pm
Invisible avatar
Lol, i wanted to do every proof i know over here (digit proof with 0.33333.... *3 = 1/3 * 3, algebraic) in high detail, but you basically answered the whole question :]